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X^2+0.18X=1180
We move all terms to the left:
X^2+0.18X-(1180)=0
a = 1; b = 0.18; c = -1180;
Δ = b2-4ac
Δ = 0.182-4·1·(-1180)
Δ = 4720.0324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.18)-\sqrt{4720.0324}}{2*1}=\frac{-0.18-\sqrt{4720.0324}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.18)+\sqrt{4720.0324}}{2*1}=\frac{-0.18+\sqrt{4720.0324}}{2} $
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